the product of two consecutive square numbers is 144 .What are the two numbers ?
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Answer:
Step-by-step explanation:
Let the two consecutive square no. is x and x+1
According to question
x^2 + ( x+1)^2 = 144
x^2 + x^2 + 1 + 2x = 144
2x^2 + 2x = 144 - 1
2x^2 + 2x - 143 = 0
2x^2 + 13x - 11x -143 = 0
2x(x + 13) - 11(x + 13) = 0
(x+13) (2x - 11) = 0
x = -13 and 11/2 .
Answered by
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Answer: 3 and 4
let the 2 no. be x and x+1
a/q
=>x²(x+1)²=144.................eq 1
squaring both sides
=>x(x+1)=12
=>x²+x-12=0
=>x²+(4-3)x-12=0
=>x²+4x-3x-12=0
=>x(x+4)-3(x+4)=0
=>(x+4)(x-3)=0
either x=3 or x=4
when x=3
one no. is 3 the other no. is 4
when x=4
one no.is 4 and other no. is 5, which does not satisfy eq 1
therefore the required 2 no.s are 3 and 4
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