Question

The product of two consecutive terms of arithmetic sequence is 5, 8, 11... 598 find the position number

Answer 1

Answer:

7th & 8th position.

Step-by-step explanation:

Given AP = 5,8,11

first term (a) = 5

Common difference (d) = 8-5 = 3

let the position of the required term be "n".

so, the position of consecutive term would be "n+1"

nth term = a+(n-1)d = 3n+2

(n+1)th term = 3n+5

according to the question,

(3n+2)(3n+5) = 598

9n²+15n+6n+10=598

9n²+21n-588= 0

3n²+7n-196=0

according to quadratic equations,

n= 42/6 & n= -56/6

since the position cannot be negative ,

n = 42/6 = 7

Therefore the position of two consecutive terms are 7 th & 8th terms .

Hope it helps you dude. If so tag me as brainliest please.

Have a great day.

Answer 2

Answer:

7 and 8 is the consecutive numbers