The product of two consicutive integers is 11 more than their sum
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hey mate ,
step by step explanation is attached
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Answer:
Step-by-step explanation:
If the integers are
m
and
m
+
1
, then we are given:
m
×
(
m
+
1
)
=
m
+
(
m
+
1
)
+
11
That is:
m
2
+
m
=
2
m
+
12
Subtract
2
m
+
12
from both sides to get:
0
=
m
2
−
m
−
12
=
(
m
−
4
)
(
m
+
3
)
This equation has solutions
m
=
−
3
and
m
=
4
We were told that
m
and
m
+
1
are positive, so we can reject
m
=
−
3
, leaving the unique solution
m
=
4
.
So the integers are
m
=
4
and
m
+
1
=
5
.
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