the product of two digit number is 2160 and thier g. c. m is 12,the first number is? (please also explain (a, b) co prime values in the solution)
Answers
The sum of two numbers is 216 and their HCF is 27. What are the numbers?
Let the numbers be x and y.
x+y = 216. Since their HCF is 27, the two numbers must be multiples of 27.
216/27 = 8.
So the numbers can be
27 and 189
54 and 162
81 and 135
The LCM of two number is 4800 and their HCF is 160. If one of the number is 160, then what is the second number?
If we have two numbers a and b then
a*b = LCM(a,b)*HCF(a,b)
Putting the values of a and b as a=160 , LCM(a,b) = 4800 , HCF(a,b) = 160
We get b = (4800*160)/160 = 4800
Hope it helps !!!
The HCF of two numbers is 6 and their LCM is 72. If one number is 24, what is the other number?
HCF ×LCM = PRODUCT OF TWO NUMBERS
6 × 72 = 24 × Other number
Other number =( 6 × 72)/24
=18 ans
The product of two numbers is 2,160 and their HCF is 12 . What is their LCM?
Product of two numbers = 2160.
HCF of the two numbers = 12.
Hence LCM of the two numbers = 2160/12 = 180.
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