Question

The product of two digit number is 486 and their LCM is 54. What is their HCF

Answer 1

Given,

• Product of two digit number is 486.
• LCM is 54.

To Find,

• Their HCF.

According to question,

Let, HCF of two digit number be "R".

We know that,

HCF × LCM = Product of two numbers

[ Put the values ]

⟶ R × 54 = 486

⟶ R = 486/54

⟶ R = 9

Therefore,

The HCF of two digit numbers is 9.

Answer 2

$\bf Given \begin{cases} & \sf{LCM\;of\;two\;numbers = \bf{54}} \\ & \sf{Product\;of\;two\;numbers = \bf{486}} \end{cases}$

we have to find, HCF of two numbers

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

☯ Let the HCF of two numbers be x.

⠀

We know that,

⠀

$\star\;{\boxed{\sf{\purple{HCF \times LCM = Product\;of\;two\;numbers}}}}$

Now, Putting values,

⠀

$:\implies\sf HCF \times 54 = 486$

$:\implies\sf HCF = \cancel{ \dfrac{486}{54}}$

$:\implies{\boxed{\sf{\pink{HCF= 9}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;the\;HCF\;of\;two\;numbers\;is\; \bf{9}.}}}$

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\qquad\qquad\boxed{\underline{\underline{\bigstar \: \bf\:More\:to\:know\:\bigstar}}}$

$\sf\blue{LCM \: (least \: common \: multiple)}$ Least number which is exactly divisible by two or more numbers.

$\sf\red{HCF \: (Highest \: common \: factor)}$ Highest factor present between two numbers.