Question

the product of two fraction is 1/4 if one of the fraction is 2/3 than the another fraction is​

Answer 1

hope this will help you in your work

Answer 2

Solution :

It is given that the product of two fractions is 1/4. One of the two fractions is 2/3. We have to find the other fraction. Let us assume that this other fraction is x/y. Now

$\dfrac{2}{3} \times \dfrac{a}{b} = \dfrac{1}{4} \\\\ \dfrac{a}{b} = \dfrac{1}{4} \times \dfrac{3}{2} = \dfrac{3}{8}$

Hence the other fraction is 3/8. This is the required answer.

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Additional Information :

$\boxed{\begin{minipage}{6 cm}\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{C} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{C} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}\end{minipage}}$

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