Math, asked by mineshthakor960, 2 months ago

The product of two integers x and y is 2, 17, 728 and LCM (x, y) = 42 X HCF(x, y).Find the HCF and LCM of x and y.

Answers

Answered by ANGEL1321
12

Answer:

Step-by-step explanation:

Product of two numbers x and y= 217728

LCM of x and y= 42 (HCF of x and y)

Let HCF be 'm'.

So LCM= 42× m = 42m.

42m × m= 217728

42m^{2} = 217728

m^{2} = \frac{217728}{42\\} = 5184

m= \sqrt{5184} = 72

LCM= 42 ×  72 = 3024

Answered by pmeet5784
5

Answer:

product x and y=217728

lcm(x,y)=42×hcf(x,y)

let the hcf be x

so,lcm=42×x

=42x

42x×x=217728

√42=217728

x=5184

x=72

lcm=42×72

=3024

Similar questions