Question

the product
of two natural no is 9222 if they
differ by 19 then find out the sum of number​

Answer 1

Answer:

If they differ by 19 then find out the sum of the numbers. Explanation: Let 'a' and 'b' be the two numbers where (a > b). It is given that a*b = 9222 and a - b = 19 Solving for 'a' and 'b', b(b+19) = 9222, b = 87 or -106 'b' can't be -106 as 'b' is a natural number.

Step-by-step explanation:

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Answer 2

Thus, the sum of the two numbers is 193.

Given:

The product of two natural no is 9222 and they

differ by 19.

To find:

The numbers.

Solution:

To determine the numbers we have to follow the below steps as follows-

Let the numbers be x and y.

The product of two natural no is 9222 and they

differ by 19.

So, we can write-

$xy = 9222 \\ x - y = 19$

Now we know that-

${(x + y)}^{2} = {(x - y)}^{2} + 4xy$

${(x + y)}^{2} = {19}^{2} + 4 \times 9222$

${(x + y)}^{2} = 361 + 36888 \\{(x + y)}^{2} = 37249 \\ x + y = \sqrt{37249} \\ x + y =193$

Thus, the sum of the two numbers is 193.

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