The product of two number is 136. The first number is 1 more than twice the other. Find the two numbers.
Answers
Answered by
1
Answer:
it is tooo hard for me sorry.
Answered by
3
Step-by-step explanation:
Explanation:
Let the first number be
n
1
Let the second number be
n
2
Let the third number be
n
3
Given that
n
1
n
2
=
2
3
Given that
n
2
n
3
=
5
8
Given that
n
1
+
n
2
+
n
3
=
98
.................................(1)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
n
1
n
2
=
2
3
Write this as
3
n
1
=
2
n
2
So
n
1
=
2
3
n
2
.................................................(2)
,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
n
2
n
3
=
5
8
Write this as
8
n
2
=
5
n
3
So
n
3
=
8
5
n
2
......................................................(3)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Substitute (3) and (2) into (1) giving:
n
1
+
n
2
+
n
3
=
98
→
2
3
n
2
+
n
2
+
8
5
n
2
=
98
⇒
n
2
(
10
+
1
+
24
15
)
=
98
⇒
n
2
=
30
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