the product of two number is 15 and 2/3 if one of the number is 2 and1/6 .find the other number?
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It seems you are using a number system with at least 6 digits. Let us assume the numbers are in base nn.
We try to solve.
x∗y=15nx∗y=15n
x=5nx=5n
Let us rewrite this (in base 1010):
x∗y=n+5x∗y=n+5
x=5x=5
Now it is easy to obtain the result:
5y=n+55y=n+5
⇒y=n5+1,n≥6⇒y=n5+1,n≥6
Assuming you are using base 66: y=2.2y=2.2
Assuming you are using base 77: y=2.4y=2.4
Assuming you are using base 88: y=2.6y=2.6
Assuming you are using base 99: y=2.8y=2.8
Assuming you are using base 1010: y=3.0y=3.0
Assuming you are using base 1111: y=3.2y=3.2
Assuming you are using base 1212: y=3.4y=3.4
Assuming you are using base 1313: y=3.6y=3.6
…
Assuming you are using base 205205: y=42y=42
As we can see, the base is of course 205205, and the solution (like always…) 42;-)
Therefore, the complete equation is:
5205∗4210=15205
We try to solve.
x∗y=15nx∗y=15n
x=5nx=5n
Let us rewrite this (in base 1010):
x∗y=n+5x∗y=n+5
x=5x=5
Now it is easy to obtain the result:
5y=n+55y=n+5
⇒y=n5+1,n≥6⇒y=n5+1,n≥6
Assuming you are using base 66: y=2.2y=2.2
Assuming you are using base 77: y=2.4y=2.4
Assuming you are using base 88: y=2.6y=2.6
Assuming you are using base 99: y=2.8y=2.8
Assuming you are using base 1010: y=3.0y=3.0
Assuming you are using base 1111: y=3.2y=3.2
Assuming you are using base 1212: y=3.4y=3.4
Assuming you are using base 1313: y=3.6y=3.6
…
Assuming you are using base 205205: y=42y=42
As we can see, the base is of course 205205, and the solution (like always…) 42;-)
Therefore, the complete equation is:
5205∗4210=15205
Muskan5785:
hi
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Let the Nos be X and Y
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