the product of two number is 1575 and the ratio of the number is 9:7. find the sum of the number
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Answered by
7
let the ratio be 9x and 7x
accordimg to question , 9x × 7x =1575
63x square = 1575
x square = 1575/63
x square =25
x = _/ 25
x =5
so , 9x = 9×5 =45
7x = 7× 5 = 35
their sum willbe 45+35=80
accordimg to question , 9x × 7x =1575
63x square = 1575
x square = 1575/63
x square =25
x = _/ 25
x =5
so , 9x = 9×5 =45
7x = 7× 5 = 35
their sum willbe 45+35=80
Answered by
1
the numbers are in the ratio 9:7
let the common multiple be x
therefore the numbers are 9x&7x
product of numbers=9x×7x
1575=63x^2...................(given)
1575/63=x^2
25=x^2
x=5
two numbers:
9x=9(5)=45
7x=7(5)=35
sum of the two no.
45+35=80
Therefore sum of these number is 80
let the common multiple be x
therefore the numbers are 9x&7x
product of numbers=9x×7x
1575=63x^2...................(given)
1575/63=x^2
25=x^2
x=5
two numbers:
9x=9(5)=45
7x=7(5)=35
sum of the two no.
45+35=80
Therefore sum of these number is 80
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