The product of two number is 2l and diffexno
is 4 then the ratio of the sum of their
cubes to the difference of their cutes is 185:158
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Step-by-step explanation:
Let the number be x and y.
x−y=4
xy=21
x ^3 − y ^3 = (x−y)[x^2 + y^2 + xy −2xy + 2xy]
=(x−y)[(x−y)^2 + 3xy]
=4(16+63)=4×79=316
⇒ squaring on both sides in x−y=4
(x−y)^2=(4)^2
x^2 + y^2 − 2xy = 16
adding 2xy on both sides:
⇒x^2 + y^2 - 2xy + 2xy = 16 + 2xy
⇒(x+y)^2 - 2xy = 16 + 2xy
⇒(x+y)^2 = 16 + 4xy =16+4×21 = 100
⇒ x+y=10
∴x^3 + y^3 =(x+y)[x^2 + y^2 − xy]
=(x+y)(x^2 + y^2 −xy + 2xy − 2xy)
= (10)[(x+y)^2 − 3xy]⇒10(100 − 3 × 21) = 370
Required ratio = (x^3 − y^3) /(x^3 + y^3)
=370 : 316
=185 : 158
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