Question

The product of two number is 7168 and their hcf is 16. How many pairs of numbers are possible such that above condition is satisfied? Ans-(448,16),(112,64)...plz explain

Answer 1

As the question mentions that the hcf is 16 that means the two numbers are a multiple of 16.
let these two numbers be:
16x and 16y
The product of the numbers are 7168. Which means...
(16x)*(16y)=7168
256xy=7168
xy=7168/256
xy= 28
here x,y can pair to form a product of 28 in the following ways: (1*28), (2*14), (4*7)
so the numbers are:
>1*16,28*16= 16,448
>2*16,14*16= 32,224
>4*16, 7*16 = 64,112

Answer 2

Answer:

(448,16),(112,64)

Step-by-step explanation:

hope it will useful