Question

The product of two numbers is 120, if their HCF is 2, find their LCM.

Answer 1

Answer:

60

Step-by-step explanation:

LCM(a,b)=a×b/HCF(a,b)

so ,

LCM= 120/2

= 60

Answer 2

Answer:

find factor pairs of 120

so there are 2 no.s p and q whose product is 120 and hcf is 2

10 and 12 are factor pairs of 120

their hcf = 2

Lcm of 12 and 10 = 2*2*3*5 = 60