The product of two numbers is 1575 and their quotient is 9/7 . Find the numbers . Best answer will be marked as brainliest
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Hey mate !!
Thanks for the question !!
Here's the answer !!
Given:
Product of two numbers = 1575
The quotient of two numbers = 9 / 7
To find :
The two numbers = ?
Proof :
Let the two numbers be ' x ' and ' y '. So according to the question,
= x * y = 1575
=> x = 1575 / y -----( 1 )
Also,
= x / y = 9 / 7
Cross multiplying the terms we get,
= 7x = 9y -----( 2 )
Now substitute the value of ' x ' from ( 1 ) in ( 2 ). We get,
= 7 ( 1575 / y ) = 9y
= 7 ( 1575 ) / y = 9y
= 11025 / y = 9y
Transposing ' y ' from LHS to RHS, we get,
= 11025 = 9y * y
=> 11025 = 9y²
Transposing 9 from RHS to LHS, we get ,
= 11025 / 9 = y²
= 1225 = y²
=> y = √ 1225
=> y = 35
=> x = 1575 / y
=> x = 1575 / 35
=> x = 45.
Therefore the numbers are 35 and 45.
Hope my answer helped !!
Cheers !!
Thanks for the question !!
Here's the answer !!
Given:
Product of two numbers = 1575
The quotient of two numbers = 9 / 7
To find :
The two numbers = ?
Proof :
Let the two numbers be ' x ' and ' y '. So according to the question,
= x * y = 1575
=> x = 1575 / y -----( 1 )
Also,
= x / y = 9 / 7
Cross multiplying the terms we get,
= 7x = 9y -----( 2 )
Now substitute the value of ' x ' from ( 1 ) in ( 2 ). We get,
= 7 ( 1575 / y ) = 9y
= 7 ( 1575 ) / y = 9y
= 11025 / y = 9y
Transposing ' y ' from LHS to RHS, we get,
= 11025 = 9y * y
=> 11025 = 9y²
Transposing 9 from RHS to LHS, we get ,
= 11025 / 9 = y²
= 1225 = y²
=> y = √ 1225
=> y = 35
=> x = 1575 / y
=> x = 1575 / 35
=> x = 45.
Therefore the numbers are 35 and 45.
Hope my answer helped !!
Cheers !!
aadi93:
thanks buddy
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