Question

the product of two numbers is 1575 and their ratio 9 ratio 7 find the number​

Answer 1

Answer:

45 and 35

Step-by-step explanation:

$\large \text{Let the ratio constant be k}\\\\\\\large \text{So first number is 9k and second number 7k}\\\\\\\large \text{Given their product equal to 1575}\\\\\\\large \text{So putting values here}\\\\\\\large 9k\times7k=1575\\\\\\\large k^2=\dfrac{1575}{9\times7}$

$\large k^2=25\\\\\\\large k=\sqrt{25} \ so \ k=5 \\\\\\\large \text{So first number is 9\times5=45 and second number is 7\times5=35 }\\\\\\\large \text{Verification}\\\\\\\large 7k\times9k=1575\\\\\\\large \text{L..H.S = 35\times45 }\\\\\\\large \text{L..H.S = 1575}\\\\\\\large L..H.S = R.H.S\\\\\\\large \text{Hence verified }}$

Answer 2

Answer : 45 and 35

EXPLANATION :

Given,

Product of two numbers = 1575

Their ratio = 9:7

Let the each be x

According to the problem,

9x × 7x = 1575

63x² = 1575

x² = 1575/63

x = √25

x = 5

The value of x is 5

Then,

First Number = 9x = 9(5) = 45

Second Number = 7x = 7(5) = 35

Therefore, the numbers are 45 and 35.

VERIFICATION :

9x × 7x = 1575

Substitute the numbers in the place of x.

9(45) × 7(35) = 1575

45 × 35 = 1575

1575 = 1575