the product of two numbers is 168 and the sum of these two numbers is 26 what is the largest of these two numbers
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12 and 14.....
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Explanation:
x+y=26--(1)
xy=168
squaring (1) on both sides
(x^2+y^2+2xy)= 676
x^2+y^2=676-336
x^2+y^2=340
consider
(x-y)^2=x^2+y^2-2xy=340-336=4
x-y=2--(2)
2x=28
x=14
y=12
largest is 14
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