Math, asked by gatiyalap2398, 11 months ago

The product of two numbers is 2028 and their hcf is 3 how many such pairs are possible

Answers

Answered by pattabhiratan60
0
Let the numbers 13a and 13b.

Then, 13a x 13b = 2028

ab = 12.

Now, the co-primes with product 12 are (1, 12) and (3, 4).

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