Question

the product of two numbers is 210 and their HCF is 9 if one of the numbers is twice the HCF find the other number​

Answer 1

Step-by-step explanation:

HCF=9

Product of two numbers=210

Let one number be x then, other number will be (2×9)=18

Now,

\begin{gathered}x \times 18 = 210 \\ = > x = \frac{210}{18} \\ = > x = 11.6666\end{gathered}

x×18=210

=>x=

18

210

=>x=11.6666

The second number is 11.6666 .

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Answer 2

Step-by-step explanation:

Given:-

the product of two numbers is 210 and their HCF is 9 if one of the numbers is twice the HCF .

To find:-

find the other number?

Solution:-

The product of two numbers =210

HCF of the two numbers=9

one of the numbers =twice the HCF=2(9)=18

Let the other number=X

We know that

LCM×HCF =Product of two numbers

=>LCM×9=210

=>LCM=210/9

=>LCM=70/3

Now,

=>(70/3)×9=18×X

=>630/3=18X

=>210=18X

=>18X=210

=>X=210/18

=>X=70/6

=>35/3

Answer:-

The other number=35/3

Check:-

LCM×HCF=(70/3)×9=(70×9)/3=210

Product of two numbers=210