the product of two numbers is 2160 and their HCF is 12. How many such pairs of numbers can be possibly formed
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2 pairs can be formed
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HCF = 12
Numbers = 12x and 12y
where x and y are prime to each other
Therefore, 12x*12y=2160
xy=2160 by 12*12 = 15
Since 15 = 3*5 , 1*15
Possible pairs = (36, 60) and (12, 80)
Numbers = 12x and 12y
where x and y are prime to each other
Therefore, 12x*12y=2160
xy=2160 by 12*12 = 15
Since 15 = 3*5 , 1*15
Possible pairs = (36, 60) and (12, 80)
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