Question

the product of two numbers is 2160 and their LCM is 180 find HCF​

Answer 1

HeRe Is Your Ans ⤵

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$= > hcf(a \: and \: b) = \frac{product(a \: and \: b)}{lcm(a \: and \: b)} \\ \\ = > hcf(a \: and \: b) = \frac{2160}{180} \\ \\ = > hcf(a \: and \: b) = 12$

Hence , $\fbox{hcf = 12}$

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