Question

The product of two numbers is 2352 and their hcf is 14. find the possible pairs of numbers

Answer 1

The possible pairs of numbers is 14 and 168

Answer 2

Thanks for asking this question. Here is your answer:

Let the two numbers be 14a  and 14b

14a x 14b = 2352

196 ab = 2352

ab = 2352/196

ab=12

(1,12) and (3,4) (these are the co primes of 12)

Now we will make the following pairs:

(1,12) and (3,4)

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