Question

the product of two numbers is 2560 and their LCM is 320 find their LCM

Answer 1

Hi ,

There is an error in the problem we have find HCF not LCM,

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If ' a ' and ' b ' are two positive integers , their HCF = h and LCM = l 

then

                  h × l = a × b 

                  h × l = product of two numbers 

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According to the problem ,

product of the numbers = a × b = 2560

LCM =  l = 320

h × l = product of the two numbers

h = ( product of the two numbers ) / l

 h =  2560 / 320

h = 8

Therefore ,

   Required HCF = h = 8

I hope this helps you.

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Answer 2

Answer:

⇒8

Step-by-step explanation:

Let the first no. be 'a' and the second no. be 'b'

And given that,

LCM (axb) = 320 and a x b = 2560

∴ LCM(a×b) × HCF(a×b) = a × b

⇒ 2560/320 = HCF( a×b)

⇒8 = HCF( a×b )

Here the question is wrong it should be find 'HCF not LCM'