the product of two numbers is 2560 and their LCM is 320. find their HCF.
Answers
Answered by
230
⏩⏩Hey friend your answer is here ⏬⏬
as we know that product of two no. = product of their hcf and lcm.
then, let the no. be a and b .
so , a × b = lcm (a, b) × hcf ( a,b).
since .. a× b = 2560.
then , 2560 = 320 × hcf ( a ,b).
➖) hcf (a, b) = 2560 / 320 = 8 .
hence their hcf = 8 .
☺I hope this will help u .
✔so I request you to mark it as brainliest ans.
⏳⏳↗{♡♡♡ THANK YOU ♡♡♡}.
as we know that product of two no. = product of their hcf and lcm.
then, let the no. be a and b .
so , a × b = lcm (a, b) × hcf ( a,b).
since .. a× b = 2560.
then , 2560 = 320 × hcf ( a ,b).
➖) hcf (a, b) = 2560 / 320 = 8 .
hence their hcf = 8 .
☺I hope this will help u .
✔so I request you to mark it as brainliest ans.
⏳⏳↗{♡♡♡ THANK YOU ♡♡♡}.
Answered by
105
Answer:
Step-by-step explanation:
Let the no.=a,b
And HCF and LCM=H,L
As we know a×b=H×L
So a x b =2560
And LCM=320
So
axb=320×H
2560/320
HCF 8
Plz mark as brainiest
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