Question

the product of two numbers is 2560 and their lcm is 320 find their hcf

Answer 1

If ' a ' and ' b ' are two positive integers , their HCF = h and LCM = l 

then

                  h × l = a × b 

                  h × l = product of two numbers 

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According to the problem ,

product of the numbers = a × b = 2560

LCM =  l = 320

h × l = product of the two numbers

h = ( product of the two numbers ) / l

 h =  2560 / 320

h = 8

Therefore ,

   Required HCF = h = 8

I hope this helps you.

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