Question

The product of two numbers is 2646 and HCF is 21. Therefore the LCM of two numbers is

Answer 1

Answer:

Step-by-step explanation:

let the number be 13a and 13b.

then,13a ×13b=2028

then,ab=12

the co-primes with product 12 are (1,12) (3,4)

So the required numbers are (13×1),(13×12) , (13×3) and (13×4)

The hcf is 13.

there are 2 such pairs.

Answer 2

Answer:

LCM × HCF = product of two numbers

LCM × 21 = 2646

LCM = 2646÷21

LCM = 126

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