Question

the product of two numbers is 2880 one of the numbers is 30 find the other
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Answer 1

Step-by-step explanation:

Given :-

• the product of two numbers is 2880

• one of the numbers is 30

To Find :-

• find the other product.

Solution :-

HCF× LCM = Product of 2 numbers

30 × LCM = 2880

LCM = 2880/30

LCM = 96

Hence the other product is 96

More information :-

• hcf means higest prime factor.

• lcm means lowest prime factor.

Answer 2

$\huge{\underline{\overline{\mid{\mathfrak{\purple{\:\: SOLUTION\:\:} \mid}}}}}$

$\underline{ \mathfrak{ \: AnswEr:- \: }}$

$\text{\blue{The other required number = 96}}$

$\underline{ \mathfrak{ \: Given:- \: }}$

$\text{ \orange{Product of two numbers = 2880}} \\ \text{ \orange{One of the number = 30}}$

$\underline{ \mathfrak{ \: Need \:\: to \:\: find:-\: }}$

$\text{\red{The other required number = ?}}$

$\underline{ \mathfrak{ \: \:Formula \: \: used \: \: here:- \: \: }}$

$\: \: \: \: \: \: \: \: \: \: \: \sf{HCF \times LCM = Product \:of \:two \:numbers}$

$\underline{ \mathfrak{ \: Putting\:\:the\:\:values:- \: }}$

$\sf{ \longrightarrow \: 30 \times LCM = 2880}$

$\sf{ \longrightarrow \: LCM = \dfrac{2880}{30}}$

$\sf{ \longrightarrow \: LCM = \cancel\dfrac{288}{3}}$

$\sf{ \longrightarrow \: LCM = 96}$

$\underline{ \mathfrak{ \: \: Therefore:- \: \: }}$

$\sf{\green{The \: \: other\: \: required\: \: number = \underline{ \: 96\: }}}$

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