The product of two numbers is 320, and their difference is 4. What are the two numbers?
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Answer: 20 and 16
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Let the first number = x
Let the second number = (x - 4)
According to question :
x(x - 4) = 320
x² - 4x = 320
x² - 4x - 320 = 0
D = b² - 4ac
D = (-4)² - 4(1)(-320)
D = 16 + 1280
D = 1296
x = - b + √D/ 2a or - b - √D/2a
x = + 4 + √1296/ 2 or + 4 -√1296 / 2
x = + 4 + 36 / 2 or + 4 - 36 / 2
x = 40/2 or - 32/2
x = 20 or - 16
Hence
The first number = x = 20
The second number = x - 4 = 20 - 4 = 16
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Let the second number = (x - 4)
According to question :
x(x - 4) = 320
x² - 4x = 320
x² - 4x - 320 = 0
D = b² - 4ac
D = (-4)² - 4(1)(-320)
D = 16 + 1280
D = 1296
x = - b + √D/ 2a or - b - √D/2a
x = + 4 + √1296/ 2 or + 4 -√1296 / 2
x = + 4 + 36 / 2 or + 4 - 36 / 2
x = 40/2 or - 32/2
x = 20 or - 16
Hence
The first number = x = 20
The second number = x - 4 = 20 - 4 = 16
Hope you like it please mark as brainliest and please follow me
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