Question

the product of two numbers is 36 their sum is 20 what are the numbers​

Answer 1

$\large \bold{ \underline{ \: \:Answer \: \: }}$

$\to \bold{First \: number = 18 \: or \: 2} \\ \bold{</p><p> \to Second \: number = 2 \: or \: 18}$

$\large \bold{ \underline{ \: \: Explanation \: \: }}$

$\bold{ \large{Let \: , \: \: }}$

$\to$ First number be = x

$\to$ Second number = 20 - x ( sum is 20 )

$\bold{ \underline{According \: to \: the \: question \: , \: \: }}$

$\to\bold{x(20-x) = 36 }\\ \\ \to \bold{</p><p>20 {x}^{2} - {x}^{2} = 36} \\ \\ \to</p><p> \bold{{x}^{2} -20x+36 = 0} \\ \\ \to</p><p> \bold{x - 18x - 2x +36 =0} \\ \\ \to \bold{</p><p>x(x-18) -2(x-18) = 0}\\ \\ \to </p><p> \bold{(x-18)(x-2) = 0} \\ \\ \to\bold{</p><p>x = 18 \: \: or \: \: 2</p><p>}$

$\therefore \: \to \bold{First \: number = 18 \: or \: 2} \\ \bold{</p><p> \: \: \: \: \to Second \: number = 2 \: or \: 18}$

Answer 2

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