The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
A.101
B.107
C.111
D.185
Answers
Answered by
63
Solutions :-
Given :
The product of two numbers = 4107
H.C.F. of these numbers = 37
Let the LCM be x
We know that,
LCM × HCF = Product of two Numbers
A/q
=> x × 37 = 4107
=> x = 4107/37 = 111
Hence,
The greater number = C) 111
Given :
The product of two numbers = 4107
H.C.F. of these numbers = 37
Let the LCM be x
We know that,
LCM × HCF = Product of two Numbers
A/q
=> x × 37 = 4107
=> x = 4107/37 = 111
Hence,
The greater number = C) 111
tudubabu314gmailcom:
yes answer is 111
Answered by
49
Answer : Option ( C ) - 111.
Explanation -
Given :
Product of two numbers = 4107
HCF = 37 .
we know ,
Product of two numbers = HCF x LCM
Simplifying by 37.
The Other Number is 111.
Verify -
37 x 111 = 4107.
Hence :
Explanation -
Given :
Product of two numbers = 4107
HCF = 37 .
we know ,
Product of two numbers = HCF x LCM
Simplifying by 37.
The Other Number is 111.
Verify -
37 x 111 = 4107.
Hence :
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