Question

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Answer 1

Let 37a & 37b be the numbers then 37a*37b = 4107 ⇒ab = 3

Co prime with product 3 are (1,3)

Hence, the required numbers are (37*1 , 37*3) i.e (37,1) (37,111)

So the greater no =111

Answer 2

Given :

Product of two numbers = 4107

HCF = 37

To Find :

The greater number.

Solution :

Assuming the LCM as - x

According to the question,

We know :

★ Product of two numbers = HCF x LCM

$\sf \implies4107 = 37 \times x$

$\sf \implies x = \dfrac{4107}{37}$

Hence, The greater number is 111.