Question

The product of two numbers is 45 and their difference is 4. the sum square of two number is

Answer 1

let the first number be x and second number be y


x*y=45.............(1)

x-y=4................(2)

squaring (2), we get,

(x-y)^2=16

opening LHS, we get,

x^2 - 2xy + y^2 = 16

using (1) in the equation, we get,

x^2 - 2(45) + y^2 = 16

x^2 - 90 + y^2 = 16

which gives,

x^2 + y^2 = 106

that is 
"x squared + y squared = 106"

Hence, your answer is 106