Math, asked by Acpboss, 9 months ago

The product of two numbers is 68306. If one of the numbers is 287, find the other.
in the year 2010, a ration shop sold 97090 kg of wheat. If equal quantity of wheat
distributed everyday, find the quantity of wheat sold per day. Also, find the quant
wheat sold altogether in the months of February and March.
75 699 female voters. In an e​

Answers

Answered by karankirat345
4

1. Product of no.s = 68306

One no. = 287

Let other no. be 'x'.

x \times 287 = 68306 \\ x = 68306 \div 287 \\ x = 238

2. Total quantity of wheat sold in the year = 97090 kg

No. of days in year 2010 = 365

Let quantity of wheat sold per day = 'y' kg.

y \times 365 = 97090 \\ y = 97090 \div 365 \\ y = 266 \: kg

Total no. of days in February and March = 28 + 31 = 59 days

Quantity of wheat sold in February and March =

59 \times 266 = 15694 \: kg

Hope this helps you...

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