Question

The product of two numbers is 700 and sum of the numbers exceeds their difference by 40. Find the numbers.
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Answer 1

Step-by-step explanation:

Let a & b be the two numbers

Then , ab=336

Also a+b=a-b+32

OR

a+b=b-a+32

because we don't know which number is greater

Let us consider first a+b=a-b+32

Here on solving we get , b=16

On substituting b=16 in ab=336

we get , a=336/16

Therefore a=21

Now let us consider a+b=b-a+32

Here on solving , a=16

Therefore b must be 21 as ab=336

Therefore either a=16 &b=21 or b=16 &a=21 is the answer

Answer 2

Answer:

Step-by-step explanation: