Question

The product of two numbers is 7680. If there HCF is 48, find their LCM

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge\underline\mathrm{GIVEN:-}$

• Product of two numbers = 7680
• HCF of those numbers = 48

$\huge\underline\mathrm{TO \:FIND:-}$

Find the LCM of the two numbers = ?

$\huge\underline\mathrm{SOLUTION:-}$

●Let the two numbers be 'a' and 'b'

➢ a $\times$ b = HCF $\times$ LCM

● According to concept :-

$\large{\boxed{\bf{\red{\star \: a \times b = HCF \times LCM \: \star }}}}$

We can put 7680 on the place of a $\times$ b 【∴ The product of the number (a $\times$b ) = 7680】

● According to conditions :-

$\longmapsto$$\sf{7680 = 48 \times LCM}$

$\longmapsto$$\sf{LCM = \cancel\dfrac{7680}{48}}$

$\longmapsto$$\large\sf\red{LCM = 160}$

$\Large\underline\mathrm{FINAL\: ANSWER:-}$

$\huge{\boxed{\boxed{\bf{\red{LCM = 160}}}}}$