Question

The product of two polynomials is 6y3-11y2+6y-1.If one polynomial is 3y2-4y+1,then find the other polynomial.

Answer 1

Answer:

so other polynomial is 2y-1.

so (2y-1)(3y²-4y+1)=6y³-11y²+6y-1

Answer 2

Answer:

The second polynomial which gives us $6y^3 - 11y^2 + 6y -1$ on multiplication with $3y^2-4y+1$   is $2y - 1$

Step-by-step explanation:

Given,

Product of the two polynomials = $6y^3 - 11y^2 + 6y -1$

One of the two polynomial = $3y^2-4y+1$

We need to find the second polynomial.

Product of two numbers, p = x * y,

Then, x = p / y

Likewise we consider the two polynomials to be two distinct variables. We need to find the quotient to get the second polynomial.

$(y^3-11y^2+6y-1)$$/$$3y^2-4y+1$

By applying the long division method to the above equation we get the quotient as $2y-1$ which is the answer as,

$(2y-1)(3y^2-4y+1)=6y^3-11y^2+6y-1$

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