Question

® The product of two positive Consecutive even integer
is 168.Assuming the amallar integer to be x,frame an

equation for the statement and find
the numbeds.​

Answer 1

x,x+1 be two consecutive no

(x)(x+1)=168

x²+x-168=0

Answer 2

ANSWER:

x is the smallest of the two consecutive even integers. Then the other

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 and

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 andx(x+2)=168⟹x2+2x−168=0⟹x2+14x−12x−168=0

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 andx(x+2)=168⟹x2+2x−168=0⟹x2+14x−12x−168=0⟹x(x+14)−12(x+14)=0⟹(x+14)(x−12)=0

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 andx(x+2)=168⟹x2+2x−168=0⟹x2+14x−12x−168=0⟹x(x+14)−12(x+14)=0⟹(x+14)(x−12)=0⟹x=−14orx=12

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 andx(x+2)=168⟹x2+2x−168=0⟹x2+14x−12x−168=0⟹x(x+14)−12(x+14)=0⟹(x+14)(x−12)=0⟹x=−14orx=12∵x is a positive integer. We can ignore x = - 14

x is the smallest of the two consecutive even integers. Then the other integer will be x + 2 andx(x+2)=168⟹x2+2x−168=0⟹x2+14x−12x−168=0⟹x(x+14)−12(x+14)=0⟹(x+14)(x−12)=0⟹x=−14orx=12∵x is a positive integer. We can ignore x = - 14∴the two integer are (12, 14)..

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