Question

the product of two positive consecutive integers consecutive even integers is 80. Find the integers

Answer 1

let integers be x and x+1

so ,ATQ

x(x+1) = 80

x² +x -80 = 0

by dicriminant method , you cam easily solve it ahead . or just simply tooo

Answer 2

Mark brainliest please :)

Answer:

Let the integers be:

x

x+2

x(x+2)= 80

x^2 + 2x = 80

x^2 + 2x -80 = 0

(Factorize using splitting the middle term)

x^2 + 10x - 8x - 80=0

x(x+10)-8(x+10)=0

(x-8)(x+10)

Therefore the two integers are 8 and 10 (you can check this also- 8 and 10 are consecutive even integers and they multiply into 80)