Question

The product of two positive numbers is 23. What is the sum of the squares of their
reciprocals?

Answer 1

Answer:

530 / 529

Step-by-step explanation:

23 is a prime number

Therefore, 23 and 1 are the factors

Reciprocal of 23 and 1 is 1 / 23 and 1 / 1

So square of

1 / 23 => (1)^2 / (23)^2 = 1 / 529 ...(1)

1 / 1 => (1)^2 / (1)^2 = 1 / 1  ...(2)

Adding (1) and (2)

1 / 529 + 1 / 1

= 1 / 529 + 529 / 529

= 530 / 529