The product of two positive numbers is 52. Find the two numbers if one number is 5 more than twice the other.
Answers
Answered by
8
Let two no be x & y
x*y = 52 - - - - - - (i)
x = 52/y
x = 2y + 5
52/y = 2y + 5
2y^2 + 5y - 52 = 0
2y^2 + 13y - 8y - 52 = 0
y(2y + 13) - 4(2y+13) = 0
(2y+13) (y-4) = 0
positive no hence (y-4) = 0
y = 4
x = 52/4 = 13
x*y = 52 - - - - - - (i)
x = 52/y
x = 2y + 5
52/y = 2y + 5
2y^2 + 5y - 52 = 0
2y^2 + 13y - 8y - 52 = 0
y(2y + 13) - 4(2y+13) = 0
(2y+13) (y-4) = 0
positive no hence (y-4) = 0
y = 4
x = 52/4 = 13
Similar questions