the product of two rational number is 118/40.If one of them is -24/5,find the other
Answers
Answer:
- 59/96
Step-by-step explanation:
Given, product of 2 rational numbers = 118/40 ---- I
Let's assume that the first rational number = (a/b) and the second rational number = (c/d) respectively
In the question, it is mentioned that one of the rational number if -24/5
Let us assume (a/b) = -24/5
Writing equation I:
LHS: (a/b) × (c/d)
RHS: 118/40
So, equating LHS = RHS
⇒(a/b) × (c/d) = 118/40
Substituting (a/b) = -24/5 in the above equation.
⇒ -24/5 × (c/d) = 118/40
⇒ (c/d) = - [(5/24)×(118/40)]
⇒ (c/d) = - [(5 × 118)/(24×40)]
⇒ (c/d) = - [(5×2×59)/(24×5×2×4) (Cancelling 5×2 as common factors in both the Numerator and Denominator)
⇒ (c/d) = - [59/(24×4)]
⇒ (c/d) = - 59/96
⇒ The second rational number is (c/d) = - 59/96 (Ans.)
Answer:
59/96
Step-by-step explanation:
Given, product of 2 rational numbers = 118/40 ---- I
Let's assume that the first rational number = (a/b) and the second rational number = (c/d) respectively
In the question, it is mentioned that one of the rational number if -24/5
Let us assume (a/b) = -24/5
Writing equation I:
LHS: (a/b) × (c/d)
RHS: 118/40
So, equating LHS = RHS
⇒(a/b) × (c/d) = 118/40
Substituting (a/b) = -24/5 in the above equation.
⇒ -24/5 × (c/d) = 118/40
⇒ (c/d) = - [(5/24)×(118/40)]
⇒ (c/d) = - [(5 × 118)/(24×40)]
⇒ (c/d) = - [(5×2×59)/(24×5×2×4) (Cancelling 5×2 as common factors in both the Numerator and Denominator)
⇒ (c/d) = - [59/(24×4)]
⇒ (c/d) = - 59/96
⇒ The second rational number is (c/d) = - 59/96 (Ans.)