Question

the product of two rational number is -16/ 9 if one of the numbers is -4/3 find the other​

Answer 1

$\sf{Let \:another\:number \:=\:x}$

A.T.Q

$\sf{x \times (\frac{-4}{3})\:=\: \frac{-16}{9}}$

$\sf{x \:=\:\frac{\frac{-16}{9}}{\frac{-4}{3}}}$

$\sf{x \:=\:\frac{\frac{\cancel{-16}}{\cancel{9}}}{\frac{\cancel{-4}}{\cancel{3}}}}$

$\sf{x\:=\:\frac{4}{3}}$

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Answer 2

Answer:

Let the other no. be x.

ATQ

-4/3 × x = -16/9

=> x = 16/9 × 3/4 = 4/3

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