Question

The product of two rational number is -16/9. If one of them is -4/3. Find the other

Answer 1

$\huge\star \: {\sf{\green{Given}}}$

✪ The product of the two rational number $\huge {\frac{-16}{9}}$

✪ one of them is $\huge {\frac{-4}{3}}$

$\huge{\bf{\blue{\underline{To:Find:-}}}}$

✪ The other number.

$\huge{\bf{\pink{\underline{Solution:-}}}}$

Let the other number be ${X}$

${\bf{\underline{A. T. Q, }}}$

${\implies{\bf{X(\frac{-4}{3})= \frac{-16}{9}}}}$

${\implies{\bf{x=\frac{16×3}{4×9}}}}$

${X = \frac{4}{3}}$

so, the other number is $\huge {\frac{4}{3}}$.

Moreover,

The products is $\huge {\frac{-16}{9}}$

So, $\huge{\bf{\frac{4}{3}×\frac{-4}{3}}}$

$\huge {\frac{-16}{9}}$

$\large{Therefore ,LHS=RHS}$