Question

the product of two rational number is 17/65.If one of the rational numbers is -51/169, find the other.
(NOTE:My answer is coming -13/15 but book's answer is -15/13) Help me!!​

Answer 1

Answer:

-13/15

Step-by-step explanation:

Let the other no be x.

$\frac{-51}{169} * x = \frac{17}{65}$

x = $\frac{17}{65}$ ÷ $\frac{-51}{169} = \frac{17}{65} * \frac{-169}{51}$

                    = $\frac{1}{5} * \frac{-13}{3}$

                    = $\frac{-13}{15}$

Which Book question is this

Answer 2

☯GIVEN :

• Product = $\bf {\dfrac{17}{65}}$

• One Rational Number = $\bf {\dfrac{-51}{169}}$

☯TO FIND :

• Other Rational Number.

➲SOLUTION :

Let the other rational number be x.

• ✞According to the question :

$\implies \sf{ \dfrac{ - 51}{169} \times x = \dfrac{17}{65} }$

$\implies \sf{ \dfrac{ - 51x}{169} = \dfrac{17}{65} }$

• By cross multiplication :

$\implies{ \sf{ - 51x \times 65 = 169 \times 17}}$

$\implies {\sf{ - 3315x = 2873}}$

• Dividing both sides by -3315 :

$\implies {\sf{x =\dfrac{2873}{-3315}}}$

• Dividing both numerator and denominator by 221 :

$\implies {\sf{ x = \dfrac{ \cancel{2873}}{ \cancel {- 3315}}}}$

• After , dividing both numerator and denominator by 221 :

$\implies{ \underline{\huge{\boxed{ \purple{ \bf{ x = \dfrac{ -13}{15} }}}}}}$

$\huge {\red {\therefore }}$ Required number = $\bf{ \dfrac{ - 13}{15}}$ .