Question

the product of two rational number is 5 upon 18 if one of them is minus 3 upon 20 find the other ​

Answer 1

ATQ, the product of two rational number is 5/18 and one of them is minus -3/20

let the other one be x

➡ x(-3/20) = 5/18

➡ -3x/20 = 5/18

➡ -3x = 5/18 × 20

➡ -3x = 5/9 × 10

➡ -3x = 50/9

➡ x = 50/9 × 1/-3

➡ x = 50/-27 = -50/27

hence, the other rational number is -50/27

verification :-

= -50/27 × -3/20

= 5/9 × 1/2

= 5/18

hence verified.

Answer 2

• Product of two rational number is $\dfrac{5}{18}$

• One number is $\dfrac{-3}{20}$

_______________ [ GIVEN ]

• We have to find the other number.

___________________________

• Let other number be M.

We know that ..

Product of two numbers = LCM × HCF

But here .. no LCM and HCF is given. Instead of that a number is given and we have to find the other number.

=> $\dfrac{5}{18}$ = $\dfrac{-3}{20}$ × M

=> $\dfrac{5}{18}$ = $\dfrac{-3M}{20}$

=> $\dfrac{5}{18}$ × 20 = - 3M

=> $\dfrac{50}{9}$ = - 3M

=> - 3M = $\dfrac{50}{9}$

=> - M = $\dfrac{50}{9}$ × $\dfrac{1}{3}$

=> - M = $\dfrac{50}{27}$

=> M = $\dfrac{-50}{27}$

______________________________

✡ Verification :

According to question we have equation :

$\dfrac{5}{18}$ = $\dfrac{-3}{20}$ × M

From above calculations we have M = $\dfrac{-50}{27}$

Put value of M in above equation

=> $\dfrac{5}{18}$ = $\dfrac{-3}{20}$ × $\dfrac{-50}{27}$

=> $\dfrac{5}{18}$ = $\dfrac{5}{18}$

_____________________________