the product of two rational number is minus 12 upon 35 if one of them is 3 upon 5 find the absolute value of the difference of two rational numbers
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Let the no. be x
(3/5)×x=-12/35
x=(-12×5)/(35×3)
x=-4/7
Difference =3/5-(-4/7)
=3/5+4/7=41/35
Absolute value of x :
=|41/35|
=41/35
(3/5)×x=-12/35
x=(-12×5)/(35×3)
x=-4/7
Difference =3/5-(-4/7)
=3/5+4/7=41/35
Absolute value of x :
=|41/35|
=41/35
piyush463:
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Answered by
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↑ Here is your answer ↓
_____________________________________________________________
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Let the other rational number be 'x'
Given that
Now, difference of the numbers
_____________________________________________________________
_____________________________________________________________
Let the other rational number be 'x'
Given that
Now, difference of the numbers
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