the product of two rational numbers is -12 By 35 if one of them is 3/5 find the absolute value of the difference of two rational numbers
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Answered by
5
x*3/5=-12/35
x=-12/35×5/3
x=-4/7
difference= 3/5-(-4/7)=41/35
x=-12/35×5/3
x=-4/7
difference= 3/5-(-4/7)=41/35
prernagautam:
but it is not a answer correctly answer is 41/35 how
Answered by
8
Here is your answer :-
Given :-
Product of two numbers = (-12/35)
First number = 3/5
We have to find the difference of two numbers.
Let the second number be x.
A/q,
➡ x * 3/5 = ( -12/35 )
➡ x = (-12/35) * ( 5/3 )
➡ x = (-4/7 )
Second number is (-4/7).
Now, the difference of two numbers -
➡( 3/5 ) - (-4/7)
➡ (3/5 ) + ( 4/7 )
➡ (21 + 20) / 35.
➡ 41/35.
Answer is 41/35.
Hope it will help you !!!
Given :-
Product of two numbers = (-12/35)
First number = 3/5
We have to find the difference of two numbers.
Let the second number be x.
A/q,
➡ x * 3/5 = ( -12/35 )
➡ x = (-12/35) * ( 5/3 )
➡ x = (-4/7 )
Second number is (-4/7).
Now, the difference of two numbers -
➡( 3/5 ) - (-4/7)
➡ (3/5 ) + ( 4/7 )
➡ (21 + 20) / 35.
➡ 41/35.
Answer is 41/35.
Hope it will help you !!!
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