Question

The product of two rational numbers is -2/3 If one number is 3/7 then find the other.​

Answer 1

Answer:

Given that,

The Product of Two Rational Numbers = -2/3

One of the Two Numbers = 3/7

Let the Other Number be x.

3/7× x = -2/3

x = -2/3÷3/7

x = -2/3×7/3

x = -14/9

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Answer 2

Answer:

The other number is $( - \frac{2}{7} )$

Step-by-step explanation:

Given,product of two rational numbers is -2/3.

Let one number be x and other number be y.

According to question,

$x \times y = ( - \frac{2}{3} )....(1)$

It is also given,one number is $\frac{3}{7}$

So,from equation (1),

$x \times \frac{3}{7} = - \frac{2}{3} \\ x = - \frac{2}{3} \times \frac{3}{7}$

$x = - \frac{2}{7}$

Therefore, required other number is $( - \frac{2}{7} )$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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