Question

the product of two rational numbers is (-28/81) if one of them is -2/3 find the other?​

Answer 1

Given

$\bold{Product \ of \ 2 \ rational \ numbers} = \dfrac{-28}{81} \\\bold{ One \of \ the \ rational \ numbers} = \dfrac{-2}{3}$

Let the other number be x.

$\implies \dfrac{-2}{3}x= \dfrac{-28}{81}$

$\implies x = \dfrac{-28}{81} * \dfrac{3}{-2}$

$\implies x = \dfrac{14}{27}$

$\boxed{\boxed{\bold{Therefore, \ the \ other \ rational \ number \ is \ \frac{14}{27}}}}}$

NOTE

• Rational numbers are a part of real numbers.
• They can be +ve or -ve.
• They can fractions or whole numbers.

                                                           

Answer 2

Answer:

$answer \\ Given</p><p></p><p></p><p></p><p>Let the other number be x.</p><p></p><p>\implies \dfrac{-2}{3}x= \dfrac{-28}{81}⟹3−2x=81−28</p><p></p><p>\implies x = \dfrac{-28}{81} * \dfrac{3}{-2}⟹x=81−28∗−23</p><p></p><p>\implies x = \dfrac{14}{27}⟹x=2714</p><p></p><p></p><p></p><p>NOTE</p><p></p><p>Rational numbers are a part of real numbers.They can be +ve or -ve.They can fractions or whole numbers.</p><p></p><p>                                                           </p><p></p><p>$