Question

the product of two rational numbers is -2by3 If one of them is 16by39 find the other​

Answer 1

Given:-

• Product of two rational number is $\dfrac{-2}{3}$
• One number is $\dfrac{16}{39}$

To find:

• Another number?

Solution:

Given that product of two numbers are $\dfrac{-2}{3}$ in which one number is $\dfrac{16}{39}$.

• Let suppose that another (required) number is x

Therefore,

$\dfrac{16}{39}×x\:=\:\dfrac{-2}{3}$

$\implies\dfrac{16x}{39}\:=\:\dfrac{-2}{3}$

$\implies{16x\:=\:\dfrac{-2}{3}×39}$

$\implies{16x\:=\:\dfrac{-78}{3}}$

$\implies{16x\:=\:-26}$

$\implies{x\:=\:\dfrac{-26}{16}}$

$\implies{x\:=\:\dfrac{-13}{8}}$

Therefore,

• Value of another number is $\dfrac{-13}{8}$

Answer 2

A N S W E R :

• Value of another number is -13/8.

Given :

• Product of two rational number is -2/3

• One number is 16/39

To find :

• Find Another Number ?

Solution :

• Let the other number be x

=> x × (-2/3) = 16/39

=> x = 16/39 ÷ (-2/3)

=> x = 16/39 × -3/2

=> x = -13/8

Hence,

• Value of another number is -13/8.